An electric field is = sign(x)?(260 N/C)?, where sign(x) equals -1 ifx 0. A cyli

Question

An electric field is = sign(x)?(260 N/C)?, where sign(x) equals -1 ifx 0. A cylinder of length L = 22cm and radius R = 2.8cm has its center at the origin and its axis along the x axis such that one end is at x= +11 cm and the other is at x = -11 cm. (a) What is the flux through each end? N .m^2/C (+x end) N . m^2/C (-x end) (b) What is the flux through the curved surface of the cylinder? N? m^2/C (c) What is the net outward flux through the entire cylindrical surface? N .m^2/C (d) What is the net charge inside the cylinder? C

Explanation / Answer

d)

E=sgn(x).260N/Ci

=+1*260N/Ci

=260N/Ci

E=lamda/(2*pi*epsilon*R)

lamda=q*L

E=q*L/(2*pi*epsilon*R)

E=2KqL/R

K=9*109

260=2*9*109*q*11/2.8

q=3.676*10-11c

b)

flux=q/epsilon

=415.837wb

a)

positive end x=11cm

flux=q/epsilon

=4.15837wb

negative end x=-11cm

flux=q/epsilon

=4.15837wb

c)

net outward flux

=sum of fluxes at positive and negative end

=8.30wb

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