An electric dipole (p=5x10 -30 C m) is located in anelectric field of magnitude

Question

An electric dipole (p=5x10-30C m) is located in anelectric field of magnitude 600V/m. What is the energydifference between the parallel and anti-parallelconfigurations? *i thought that you would just use the equationU=q*Vba , however I still got the problem wrong.Did I use the wrong equation? If so, what equation am I supposed tobe using, and how do I apply it? An electric dipole (p=5x10-30C m) is located in anelectric field of magnitude 600V/m. What is the energydifference between the parallel and anti-parallelconfigurations? *i thought that you would just use the equationU=q*Vba , however I still got the problem wrong.Did I use the wrong equation? If so, what equation am I supposed tobe using, and how do I apply it?

Explanation / Answer

We know that               U = -p.E                   = -pEcos when they are parallel U = -pE When they are antiparallel U = pE now the eneryg difference between the configuration is                 dU = pE-(-pE)                       =2pE Given that                   p = 5x10-30C m and E =600V/m. now substitute the values                                                                      

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