(a) What will be the new time constant? = s Treat the system as a simple RC circ

Question

(a) What will be the new time constant?
=   s
Treat the system as a simple RC circuit with an equivalent capacitance for C and an equivalent resistance for R to calculate the time constant for each. Your response differs from the correct answer by more than 10%. Double check your calculations.

(b) What will be the maximum current in the circuit (leaving the battery terminal)?
Imax =  µA

(c) What will be the new time constant?
=  s


(d) What will be the maximum current in the circuit (leaving the battery terminal)?
Imax =  µA

Explanation / Answer

New resistance is R = R1*R2/(R1+R2) = (8.2*3.7)/(8.2+3.7) = 2.54 *10^5 ohm

new capacitance is C = C1+C2 = 4.7+4.5 = 9.2 uF

then time constant is R*C = 2.54*10^5*9.2*10^-6 = 2.34 s

B) maximum current is Imax = Vmax/R = 12/(2.54*10^5) = 47.24 uA

C) now R = R1+R2 = 8.2+3.7 = 11.9*10^5 ohm

C = C1*C2/(C1+C2) = (4.5*4.7)/(4.5+4.7) = 2.3*10^-6 F

time constant T = R*C = 11.9*10^5*2.3*10^-6 = 2.74 s

D) maximum current Imax = Vmax/R = 12/(11.9*10^5) = 10.08*10^-6 A = 10.08 uA

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