Chapter 04, Problem 098 Your answer is partially correct. Try again. Review Inte

Question

Chapter 04, Problem 098 Your answer is partially correct. Try again. Review Interactive Solution 4.98 before starting this problem. Two forces, F, and F, act on the 7.00-kg block shown in the drawing. The magnitudes of the forces are F1=75.3 N and F2=38.6 N. Take the positive direction to be to the right. Find the horizontal acceleration of the block, including sign, the fo cesare F =753NandF2-38.6N Takethepositi lem Twofrces, F and Fract on the 7.00-kg block Shown in 0.0 F, 7.00 kg NumberTT 1.693 Unit m/s^2 the tolerance is +/-6%

Explanation / Answer

by using free body diagram

F2 in left side

F1 has two componet

in horizontal direction total force

Fx = F1cos70 - F2

given : F1 = 75.3 N

F2 = 38.6 N

Fx = -12.85 N

ax = Fx/m

given m = 7 kg

ax = -1.835 m/s^2

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