An electron moving to the right at 4.0%the speed of light enters a uniform elect

Question

An electron moving to the right at 4.0%the speed of light enters a uniform electric field parallel to itsdirection of motion. If the electron is to be brought to rest inthe space of 5.8 cm, determine thefollowing.

(a) What direction is required for the electric field? 1 Against the direction of the velocity, tothe left. Perpendicular to the direction ofvelocity, upwards.     Perpendicular tothe direction of velocity, downwards. In the directionof the velocity, to the right.

(b) What is the strength of the field?
2 N/C

1 Against the direction of the velocity, tothe left. Perpendicular to the direction ofvelocity, upwards.     Perpendicular tothe direction of velocity, downwards. In the directionof the velocity, to the right. 1 Against the direction of the velocity, tothe left. Perpendicular to the direction ofvelocity, upwards.     Perpendicular tothe direction of velocity, downwards. In the directionof the velocity, to the right. 1

Explanation / Answer

v = 0.04c, s = 5.8 cm, a) In the direction of thevelocity, to the right. b) mv2/2 = qEs E = mv2/(2qs) = 7.06*103 N/C

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