An air-filled capacitor consists of twoparallel plates, each with an area of 7.6

Question

An air-filled capacitor consists of twoparallel plates, each with an area of 7.6 cm2, separatedby a distance of 1.70 mm. If a15.0 V potential difference is appliedto these plates, calculate the following. (a) the electric field between the plates
1 kV/m
(b) the capacitance
2 pF
(c) the charge on each plate
3 pC
An air-filled capacitor consists of twoparallel plates, each with an area of 7.6 cm2, separatedby a distance of 1.70 mm. If a15.0 V potential difference is appliedto these plates, calculate the following. (a) the electric field between the plates
1 kV/m
(b) the capacitance
2 pF
(c) the charge on each plate
3 pC
(a) the electric field between the plates
1 kV/m
(b) the capacitance
2 pF
(c) the charge on each plate
3 pC

Explanation / Answer

        Given that the areaof plates is A = 7.6cm2         separation is d =1.70mm = 1.7*10-3m          Potentialdifference is V = 15 ----------------------------------------------------------------------------    (a) Electric field is E = V /d        (b) capacitance is C =0*A/d           where0 = 8.85*10-12C2/N.m2    (c) Charge is Q = C*V                       separation is d =1.70mm = 1.7*10-3m          Potentialdifference is V = 15 ----------------------------------------------------------------------------    (a) Electric field is E = V /d        (b) capacitance is C =0*A/d           where0 = 8.85*10-12C2/N.m2    (c) Charge is Q = C*V              

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