Chapter 28, Problem 039 A horizontal power line carries a current of 4600 A rom

Question

Chapter 28, Problem 039 A horizontal power line carries a current of 4600 A rom south to north. Earth's magnetic field 57.1 s directed toward the north and s inclined downward at S the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 120 m of the line due to Earth's field (a) Number Units the tolerance is +/-8% Click if you would like to Show Work for this question: Open Show Work SHOW HINT LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM MATH HELP Question Attempts: o of 6 used SAVE FOR LATER SUBMIT ANSWER SUBMIT ANSWER

Explanation / Answer

magnetic force

F = BILsin(theta)

where theta is angle between B and I

=> F = 57.1*10^-6*4600*120*sin(40 degrees) = 20.235 N

direction INWARD

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.