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Chrome File Edit View History Bookmarks People Window Help 54%) U.s. Tue 10:34 AM Q : Baby Driver xWileyPLUS Meters to Centimeters conver Ahmad × Secure l https://edugenwileyplus.com/edugen/student/mainfr.uni Apps V WileyPLUSDifferential calcul s lyi University of South D Apple iCloud Yahoo Bing W wikipedia R Facebook y Twitter-LinkedIn D The Weather Channel Yelp » Other Bookmarks WileyPLUS Hlliday, Fundamentals of Physics, 10e Calculus-based Physics I ⅈ (PH 201-202) Home Read, Study & Practice Gradebook ORION Downloadable eTextbook Assianment> Open Assignment FULL SCREEN PRINTER VERSION BACK ASSIGNMENT RESOURCES Chapter 15, Problem 068 201-20 040 A 2.60 kg block hangs from a spring. A 370 g body hung below the block stretches the spring 2.30 cm farther. (a) What is the spring constant? (b) If the 370 g body is removed and the block is set into oscllation, find the period of the motion. (a) Number (b) Number 058 Units hapter1 Units 078 LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM Review Score Review Results by Study Question Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER All Rights Reserved. A Division of John Wiley & Sons In Version 4.24.2.4 7

Explanation / Answer

a)
Apply Hooke's law:
F = k*x
where
F = force = weight of additional mass = (0.370 kg)*(9.8 m/s²) = 3.626 N
k = spring constant = ?
x = additional stretching = 0.023 m
so
3.626 N = k * (0.023 m)
k = 158 N/m

b)

T = 2 (m/k)
where
T = period = ?
m = mass = 2.6 kg
k = spring constant = 157.65 N/m
so
T = 2 ((2.6 kg)/(157.65 N/m))
T = 0.81 s

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