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Chrome File Edit View History Bookmarks People Window Help 56% Fri 7:54 PM G Web

ID: 1873032 • Letter: C

Question

Chrome File Edit View History Bookmarks People Window Help 56% Fri 7:54 PM G WebAssign (direcx HW 04 PHYS 2EX ' e The Magnitude OI × Calculating ElectCalculating Electr x G nc to c Google s x G what is n/c in phyx c D Not Secure www.webassign.net/web/Student/Assignment-Responses/submit?dep-18273772 :: Apps Physics 270·Rave and Disco Flyer. VW Parts, Volkswag www.pdx.edu/sites Ho Stuff works wh tib The World's Health e Pallini Limoncello Liq » Other Bookmarks Roque 2. 0/1 points | Previous Answers OSUniPhys1 22.5.WA.064 My Notes Ask Your T kqx The magnitude of the net electric field at a distance x from the center and on the axis of a uniformly charged ring of radius r and total charge q is given by Enet (x2 + 372 . Consider two identical rings of radius 12.0 cm each, located as shown in the diagram below. The charge per unit length on each ring is +3.75 nC/cm and d = 28.0 cm, what is the magnitude of the net electric field at the center of ring B? What is the total charge on each ring? What is the contribution to the net electric field at the center of ring B from each ring? N/C Additional Materials eBook Submit Answer Save Progress 16

Explanation / Answer

given, electric field at distance x form the center of a uniformly charged ring is given by
E = kqx/(x^2 + r^2)^3/2
where x is distance form the center of the ring and r is radius of the ring

int he given diagram
r = 0.12 m
q/2*pi*r = 3.75*10^-9 C/m
d = 28 cm = 0.28 m

hence electric field at the center of B is
Eb = k*qd/(d^2 + r^2)^3/2 = 8.98*10^9*3.75*10^-9*2*pi*0.12*0.28/(0.28^2 + 0.12^2)^3/2
Eb = 251.48077 V/m

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