Chapter 24, Problem 022 Your answer is partially correct. Try again. In Figure (

Question

Chapter 24, Problem 022 Your answer is partially correct. Try again. In Figure (a), a particle of charge +e is initially at coordinate z 50 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z =-50 nm. Figure (b) gives the work wa done by the force moving the particle versus the angle that locates the particle. The scale of the vertical axis is set by Was = 2.0 x 10-30 What is the magnitude of the dipole moment? S0 Number 1.74E-43 UnitsTc-m the tolerance is +/-2%

Explanation / Answer

We can calculate the electric field due to the electron at the dipole location.

E = kq/r^2 = (9E9*1.6022E-19)/(50E-9)^2 = 576,720 V/m

Then the energy change deltaU = 4E-30J = 2Ep

==> dipole moment p = 4E-30/(2E) = 3.4679E-36 C-m

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