Calculate the standardGibbs energy of the following reaction at 298 K from the s

Question

Calculate the standardGibbs energy of the following reaction at 298 K from the standardenthalpies and entropies of formation given in the data section atthe end of your textbook:
4 HCl (g) + O2 (g)-> 2 Cl2 (g) + 2 H2O (l)

Calculate the standardGibbs energy of the following reaction at 298 K from the standardenthalpies and entropies of formation given in the data section atthe end of your textbook:
4 HCl (g) + O2 (g)-> 2 Cl2 (g) + 2 H2O (l)

-53.07kJ/mol -74.32kJ/mol -93.05kJ/mol -148.09kJ/mol

Explanation / Answer

Formula :               G0rxn = G0 products- G0 reactants For products :           2 mol *0 kJ / mol + 2 mol * -237.13 kJ / mol       = -474.26 kJ For reactants:         4 mol * -95.27 kJ /mol + 1 mol * 0 kJ / mol     = -381.08 kJ G0rxn =  -474.26 kJ - (-381.08 kJ )                    = - 93.18 kJ

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.