A sample containing 0.2784 grams of sodium chloride (NaCl) and 0.5486 grams of m

Question

A sample containing 0.2784 grams of sodium chloride (NaCl) and 0.5486 grams of magnesium chloride (MgCl2). The chloride in the sample was precipitated by the addition of 47.8 mL of a silver nitrate solution. What is the concentration of the silver nitrate solution?
A sample containing 0.2784 grams of sodium chloride (NaCl) and 0.5486 grams of magnesium chloride (MgCl2). The chloride in the sample was precipitated by the addition of 47.8 mL of a silver nitrate solution. What is the concentration of the silver nitrate solution?

Explanation / Answer

moles of cl in Nacl= 0.2784/58.5= 4.7589 millimoles

moles of cl in Mgcl2= 2* 0.5486/95= 11.549 millimoles

total cl= 16.3079 millimoles= moles of Ag

concentration= 16.3079/47.8= 0.3411 M

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