Calculate row g for all 3 trials Calculate q water , which is the heat absorbed

Question

Calculate row g for all 3 trials

Calculate qwater, which is the heat absorbed by the solution in the calorimeter. Because the aqueous solution is very dilute, we can assume that the specific heat of the solution is the same as the specific heat of water. Use correct significant figures. Show your work only for Trial 1:

Trial 1

a

Mass of the empty calorimeter (g):

18.6g

b

Initial temperature of the HCl solution in calorimeter (

a

Mass of the empty calorimeter (g):

18.6g

b

Initial temperature of the HCl solution in calorimeter (

Explanation / Answer

Trial 1:

If the mass of the empy calorimeter is 18.6 and the mass of the calorimeter + HCl before the reaction is 68.6, the mass of the HCl solution is 68.6 - 18.6 = 50 g, and not 68.7.

Now, use this mass as the mass of water. Convert the temperatures to Kelvin (Ti = 34.5 +273.15 = 307.65 and Tf = 21.5 + 273.15 = 294.65) and use a specific heat of water of 4.184 J/g K.

QH2O = m Cp dT = 50 g * 4.184 J/g K * (307.65 - 294.65) = 2719.6 J

Trial 2:

QH2O = m Cp dT = 50 g * 4.184 J/g K * (316.35 - 294.65) = 4539.6 J

Trial 3:

QH2O = m Cp dT = 50 g * 4.184 J/g K * (324.95 - 294.65) = 6338.8 J

QH2O =

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