Calculate the frequency (f) at which an inductor of inductance (L) 5.5 mN, a res
ID: 1624311 • Letter: C
Question
Explanation / Answer
2. Xc = XL
1 / (2 pi f C) = 2 pi f L
f^2 = 1 / (4 pi^2 L C )
f = 1 / 2 pi sqrt(5.5 x 10^-3 x 11 x 10^-6)
f = 647 Hz ........Ans
Impedance = sqrt[ R^2 + (xL - Xc)^2]
= sqrt[ 10^2 + 0^2]
= 10 ohm
(b) for inductor, reactance = XL = 2 pi f L
if f is increased then reactance of inductance will increase.
For capacitor, Reactance. Xc = 1/ (2 pi f C)
if f is increased then Xc will decrease.
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