(a) What is the maximum torque on a 165 turn square loop of wire 18.0 cm on a si
ID: 1732080 • Letter: #
Question
(a) What is the maximum torque on a 165 turn square loop of wire 18.0 cm on a side that carries a 47.0 A current in a 1.60 T field? N-m (b) what is the torque when ? is 20.007 N-m Additional Materials . Reading 1.-/1 pointsOSColPhys1 22.8.044. Calculate the magnetic field strength needed on a 215 turn square loop 20.0 cm on a side create a maximum torque of 285 N-m, if the loop is carrying 25.0 A. Additional Materials Reading /2 pointsOSColPhys1 22.10.051. The force per meter between the two wires of a jumper cable being used to start a stalle is 0.276 N/m. (a) What is the current in the wires, given they are separated by 1.80 cm? (b) Is the force attractive or repulsive? O The force is attractive because the currents are in opposite directions. O The force is attractive because the currents are in the same direction. O The force is repulsive because the currents are in opposite directions. O The force is repulsive because the currents are in the same direction.Explanation / Answer
Solution,
Given,
Number of turns, N = 165
Side of square loop, a = 0.18 m
Current, I = 47 A
Magnetic field, B = 1.6 T
a) Torque, T = NIBA = 165 x 47 x 1.6 x 0.18^2 = 402.02 N.m
b) Torque, T = 165 x 47 x 1. 6 x 0.18^2 x sin(20)= 137.50 N.m
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