A baseball approaches home plate at a speed of 48.0 m/s, moving horizontally jus

Question

A baseball approaches home plate at a speed of 48.0 m/s, moving horizontally just before being hit by a bat. The batter hits a pop-up such that after hitting the bat, the baseball is moving at 54.0 m/s straight up. The ball has a mass of 145 g and is in contact with the bat for 2.40 ms. What is the average vector force the ball exerts on the bat during their interaction? F on bat= It needs to be in terms of i^ and j^

Explanation / Answer

THIS WILL BE HELPFUL FOR YOU P(initial) = 145 x 10^-3 x 40 = 5.8 N-s {on X-axis} P(final) = 145 x 10^-3 x 58 = 8.41 N-s {on Y-axis} P(applied) = ?[(5.8)^2 + (8.41)^2] =>P(applied) = 10.22 N-s By F = P/?t =>F = 10.22/(2.10 x 10^-3) =>F = 4864.80 Newton

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