A car is travelling around a horizontal circular track with radius r = 250. 0 m

Question

A car is travelling around a horizontal circular track with radius r = 250. 0 m at a constant seed v = 18. 0 m/s shown. The angle theta A = 18. 0 degree above the x axis, and the angle theta B = 60. 0 degree below the x axis. What is the magnitude of the car's acceleration? m/s2 What is the x component of the car's acceleration when it is at point A m/s2 What is the y component of the car's acceleration when it is at point A m/s2 What is the x component of the car's acceleration when it is at point B m/s2 What is the y component of the car's acceleration when it is at point B m/s2 As the car passes point B, the y component of its acceleration is increasing constant decreasing

Explanation / Answer

1)a=V^2/r=1.296
2)X component =ax=acos(90-)=asin=1.296*sin18=0.400

3)Ycomponent =acos=1.232

4)AT b x component=asin=1.296sin60=1.12

5)AT b y component=acos=0.648

6)decresig means cos increasing which gives y component increasing

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