A 2.20-kg object is hanging from the end of a vertical spring. The spring consta

Question

A 2.20-kg object is hanging from the end of a vertical spring. The spring constant is 45.0 N/m.

a) How much far is the spring stretched from its rest length? m.

The object is pulled 0.200 m downward and released from rest. Complete the following table by calculating the translational kinetic energy, the gravitational potential energy, the elastic potential energy, and the total mechanical energy E for each of the vertical positions listed. The vertical positions h indicate distances above the point of release, where h = 0 m.

Explanation / Answer

a)mg=kx

x=mg/k=2.2*9.81/45=0.4796m=47.96cm

b

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